martineau
2020-11-28 14:50:37
You can completely avoid indexing by using the itertools.combinations() function to generate all the possible pairings of the points in each sublist as illustrated below:
from itertools import combinations
l1 = [['a1','a2','a3'], ['b1','b2'], ['c1','a1']]
dicts = [{'start': start, 'end': end}
for points in l1
for start, end in combinations(points, 2)]
from pprint import pprint
pprint(dicts, sort_dicts=False)
Output:
[{'start': 'a1', 'end': 'a2'},
{'start': 'a1', 'end': 'a3'},
{'start': 'a2', 'end': 'a3'},
{'start': 'b1', 'end': 'b2'},
{'start': 'c1', 'end': 'a1'}]
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It doesn't work if I have 5 or 4 elements in a list.For example,If I have a list in the list like [a1,a2,a3,a4,a5].The output I get is [{a1,a2},{a2,a3},{a3,a4},{a4,a5},{a5,a1}] but I also need the other connections like [{a1,a3},{a1,a4},{a2,a5},{a2,a5},{a3,a5}].These values are missing @martineau .I need all the values to be paired up
Sam: Oh, OK, now I understand what you want — see updated answer.