why do I get the same output order when pthread_join( thread3, NULL); comes before pthread_join( thread1, NULL);
and when:
pthread_join( thread1, NULL); comes before pthread_join( thread3, NULL);
I know that pthread_join() waits for the thread to terminate and it worked on thread 2 but why it doesn't work here like I waited for thread 3 to terminate but it still terminates after thread 1 terminate.
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
void * print_message_function( void *ptr );
void * do_something_else( );
void * a_new_function();
int main()
{
pthread_t thread1, thread2,thread3,thread4;
char *message1 = "Thread 1 is running ";
char *message2 = "Thread 2";
int iret1, iret2,iret3;
void * (*f_ptr)();
f_ptr = do_something_else;
/* Create independent threads each of which will execute function */
iret1 = pthread_create( &thread1, NULL, print_message_function, (void*) message1);
iret2 = pthread_create( &thread2, NULL, f_ptr/*do_something_else*/, NULL);
pthread_join( thread2, NULL);
iret3 = pthread_create( &thread3, NULL,a_new_function , NULL);
pthread_join( thread3, NULL); //--------------here-------------------------------
pthread_join( thread1, NULL); //---------------here-------------------------------
return 0;
}
void * print_message_function( void *ptr )
{
int i;
for(int i=0; i < 1; i++)
printf("%s \n", (char *)ptr);
}
void * a_new_function(){
int a;
int b;
int c;
a=5;b=7;
c=b+a;
printf ("the value of c =%d\n",c);
return 0;
}
void * do_something_else( )
{
int i;
for(int i=0; i < 1; i++)
printf("%s \n", "this is do_something_else function");
}
the output in both ways is:
**this is do_something_else function
Thread 1 is running
the value of c =12**
