haskell Own version of Elem function using Foldl

I'm trying to create my own version of elem function, which returns True or False based on if the element x is inside the given array.

elem' :: Eq(t)=>t->[t]->Bool
elem' x xs = or [foldl (\acc -> \a -> if a == x then True else False) [] xs]

What I'm trying to do here is to fill the array using foldl with True/False values and then make or function, which returns True if at least one of them is True (so what I want to get). However, this code results in the following compilation error:

main.hs:11:71: error:
    * Couldn't match expected type `Bool' with actual type `[a0]'
    * In the second argument of `foldl', namely `[]'
      In the expression:
        foldl (\ acc -> \ a -> if a == x then True else False) [] xs
      In the first argument of `or', namely
        `[foldl (\ acc -> \ a -> ...) [] xs]'
   |
11 | elem' x xs = or [foldl (\acc -> \a -> if a == x then True else False) [] xs]
   |            

                                                       ^^