Regex to not match expression when before equal sign?

发布于 2020-11-30 05:13:48

foo = bar
foo        = bar
bar = foo
bar = foo asdfghjk

Is there a way to match every foo that is NOT on the left of an equal sign, so in this case the last two? I've tried:

(foo)([^=])

But that doesn't work. I'm not that good with regex, I don't know what to do from here.

Also, I am trying to pattern match in vim. I don't know if that makes a difference. I am aware the parentheses have to be escaped with \.

Questioner

nswerhun

Viewed

Wiktor Stribiżew 2020-11-30 17:25:44

You can use

:g/\vfoo(.*\=)@!/

Vim test:

The global pattern

\v - sets the very magic mode to avoid overescaping
foo - a foo string
(.*\=)@! - Vim-style classic negative lookahead that means that there can't be a = after any 0 or more chars (but line break chars) as many as possible.

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