How to make Ansible print only the task that has stdout

I have a playbook which contains multiple Tasks. I need Ansible to print only the Tasks which contains STDOUT /debug task

- hosts: "{{ v_host }}"
gather_facts: no
tasks:

- name: "Create /tmp in target in all VM's "
  file:
    path: /tmp
    state: directory
    owner: oracle
    group: oinstall
    mode: 0775

- copy:
    src: /xxx
    dest: /yyy
    owner: oracle
    group: oinstall
    force: yes
    mode: 0755

- name:  "Performing {{ patch_action }} of CPU patch on {{ v_host }} "
  shell: |
    cd /tmp
    sudo -u oracle ./patch.sh
  register: out
  
- debug: var=out.stdout_lines

I execute the playbook without -v option to have a cleaner output. The output looks like below.

ansible-playbook test.yml --extra-vars v_host=xyz.com.
    
TASK [Create /tmp in target in all VM's] ********************************************************************
ok: [ixyz.com]

TASK [copy] ********************************************************************
ok: [xyz.com]

TASK [Performing  of CPU patch on xyz.com] ***
changed: [xyz.com]

TASK [debug] *******************************************************************
ok: [xyz.com] => {
    "out.stdout_lines": [
        "Patch  123456     : applied on Tue Sep 29 10:11:58 GMT 2020", 
        "Patch description:  \"one-off\"", 
        "Patch  987654     : applied on Tue Sep 29 10:08:39 GMT 2020", 
        "Patch description:  \"One-off\"", 

    ]
}

Is there an option when i execute the playbook, it gives me the output only for the stdout/debug . The only output that i need is

TASK [debug] *******************************************************************
ok: [xyz.com] => {
    "out.stdout_lines": [
        "Patch  123456     : applied on Tue Sep 29 10:11:58 GMT 2020", 
        "Patch description:  \"one-off\"", 
        "Patch  987654     : applied on Tue Sep 29 10:08:39 GMT 2020", 
        "Patch description:  \"One-off\"", 

    ]
}