lordadmira
2020-12-06 07:04:34
If print_num() executes in a new thread, each call to it is subject to race conditions. For example print_num(12,22) could end up executing before print_num(1,11) and the output would be out of order. Or, two or more executions could be printing to STDOUT simultaneously resulting in jumbled output.
You use a semaphore to control access to a limited resource, in this case STDOUT. You can also use a lock. Basically you need to add some code to prevent print_num from executing out of called order and only one instance of it can access STDOUT at a time. You should also add code to the while loop so that it doesn't iterate until print_num is up and running and has established its place in the execution order.
HTH
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