Felipe
2020-12-07 21:02:33
I suggest you to create an object and overwrite the hashCode method. Then use the scala.util.hashing.MurmurHash3 to create your hash code.
import scala.util.hashing.MurmurHash3
object TestMurmurHash {
def main(args: Array[String]): Unit = {
val email = MyObject("my_email@google.com")
println(s"This is my email hash: $email and this is my hash: ${email.hashCode()}")
}
case class MyObject(val email: String) {
override def equals(o: Any): Boolean = {
this.hashCode() == o.hashCode()
}
override def hashCode(): Int = {
MurmurHash3.stringHash(email)
}
def mailToHash(): Int = {
MurmurHash3.stringHash(email)
}
}
}
output:
This is my email hash: MyObject(my_email@google.com) and this is my hash: -585889836
热门帖子
热门github
6
good but how to write own methot and I want use everywhere . Ex: def mailToHash
What is the point of using
Appif you are going to write themainyourself? You are just having the worst of all words. Second,hashCodehas to be consistent withequals, the best on those cases is always have a custom method.@KemalDurmus just create a method with this signature. I updated the answer. I case you need to have a Util class use this method inside a Util and any other object can use it.
thank you your solutions is good but I use diffrent solutions. I write hash helper and add project other package
def hashEmail(email: String): String = { HASH_FUNCTION.hashString(email, StandardCharsets.UTF_8).toString }