poosliver
2014-05-17 02:16:45
对于字符串，这将工作
arrayList.sort((p1, p2) -> p1.compareTo(p2));
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更好：arrayList.sort（String :: compareTo）
更好的是：
arrayList.sort(Comparator.naturalOrder())请注意，两者都
.sort(String::compareTo) and .sort(Comparator.naturalOrder())将在所有小写字母之前对所有大写字母进行排序。通常你想要的是.sort(String::compareToIgnoreCase)