如何显示找到的元素的索引号?我已经从数组中找到了最大的元素,现在我想打印该元素的索引,该索引已经找到了如何进行?
我想根据以下逻辑找到我在数组中找到的最大数量的元素?
Data Segment
msg db 0dh,0ah,"Please enter the length of the array: $"
msg1 db 0dh,0ah,"Enter a number: $"
newl db 0dh,0ah," $"
res db 0dh,0ah,"The maximum is: $"
len db ?
max db ?
Data ends
Code Segment
assume CS:Code,DS:Data
Start:
mov ax,Data
mov DS,ax
mov dx,offset msg
mov ah,09h
int 21h
call Accept
mov len,bl
mov cl,bl
mov ch,00h
mov di,1000h
back: mov dx,offset msg1
mov ah,09h
int 21h
call Accept
mov [di],bl
inc di
loop back
mov di,1000h
mov cl,len
mov ch,00h
mov dx,offset newl
mov ah,09h
int 21h
mov al,[di]
mov max,al
chk: mov bl,max
mov al,[di]
cmp bl,al
jc a
mov max,bl
jmp b
a: mov max,al
b: inc di
loop chk
mov dx,offset res
mov ah,09h
int 21h
mov bl,max
call DispNum
mov ah,4ch
int 21h
Accept proc
mov ah,01h
int 21h
call AsciiToHex
rol al,4
mov bl,al
mov ah,01h
int 21h
call AsciiToHex
add bl,al
ret
endp
DispNum proc
mov dl,bl
and dl,0f0h
ror dl,4
call HexToAscii
mov ah,02h
int 21h
mov dl,bl
and dl,0fh
call HexToAscii
mov ah,02h
int 21h
endp
AsciiToHex proc
cmp al,41h
jc sk
sub al,07h
sk: sub al,30h
ret
endp
HexToAscii proc
cmp dl,0ah
jc sk2
add dl,07h
sk2: add dl,30h
ret
endp
Code ends
end Start
你可以找到一个非常,非常类似的答案在这里如何离奇的是一个涉及最大和最小的其他交易...
mov di,1000h
因为在你的2个十六进制输入例程中,用户可以键入的最大值是“ FF”(255),所以你可以在程序的数据部分中保留该大小的缓冲区,而不仅仅是相信偏移量地址1000h不会与任何内容重叠在记忆中很重要。
Data Segment
buf db 256 dup (0)
msg db 0dh,0ah,"Please enter the length of the array: $"
...
为了解决获取最大值所在的数组元素的索引的任务,你可以将地址的当前值保存DI
在一个类似的额外寄存器中,SI
并在每次代码偶然发现一个更大的值时进行更新:
...
mov di, offset buf
mov al, [di]
mov max, al
mov si, di ; Address of the first chosen maximum
chk:
mov al, [di]
cmp al, max
jbe a
mov max, al ; Bigger than anything before
mov si, di ; Remember the address of the newest maximum
a:
inc di
loop chk
在此代码之后,你要查找的索引是从找到最大值的地址中减去数组的开头而获得的:
sub si, offset buf ; The index of the maximum
引入该SI
地址后,就不再需要单独的max变量了:
...
mov di, offset buf
mov si, di ; Address of the first chosen maximum
chk:
mov al, [di]
cmp al, [si] ; At [si] is the current maximum
jbe a
mov si, di ; Remember the address of the newest maximum
a:
inc di
dec cx
jnz chk
;;; mov al, [si] ; The maximum should you need it
sub si, offset buf ; The index of the maximum
请注意,我已经删除了较慢的loop chk
说明,并用一对替换dec cx
jnz chk
。