因此，我在Lua方面遇到了一个奇怪的问题，我使用以下函数从名为Cube的全局3D“数组”中进行设置，读取和写入。但是，似乎每次读取或写入此“数组”时，尽管Cube是全局变量，但数据仅存储在该函数使用的实例上，不能说我以前从未遇到过，非常奇怪。

-- stole this one from: https://stackoverflow.com/questions/27976526/using-a-coordinate-pair-as-a-key-in-a-lua-table
-- basically the intended use is to store a 2d table of block information for the level the turtle is on

function setUpLevel()
    local test = {_props = {}}
    local mt = {}


    local function coord2index(x, z)
        return ((x-1) * xMax) + z
    end

    mt.__index = function(s, k)
        if s._props[coord2index(k[1], k[2])] ~= nil then
            return s._props[coord2index(k[1], k[2])]
        end
    end

    mt.__newindex = function(s, k, v)
    s._props[coord2index(k[1], k[2])] = v 
    end
    mt.__call = function (t, k)
        if type(k) == "table" then print "Table" end
    end

    setmetatable(test, mt)
    return test
    --test[{1,2}] = 5
end

function setupCube()
    local cube = {}
    cube[relY]=setUpLevel()
    return cube
end

Cube = setupCube()

function readCubeData(x,y,z)
    if (Cube[y]==nil) then
        return nil
    end
    -- debug
    return Cube[y][{x,z}]
end

function storeCubeData(x,y,z,data)
    if (readCubeData(x,y,z)==nil) then
        Cube[y]=setUpLevel()
    end



    Cube[y][{x,z}]=data
    data= readCubeData(x,y,z)
    print (x,",",y,",",z,":",readCubeData(x,y,z))
    sleep(.5)
end

输出示例：

中的print语句storeCubeData()将提供的正确输出（顺序无关紧要，仅将数据对应到x，y，z值）

但是下面的打印语句 start()

function start()
    detectAndStore()
    print("=============")
    sleep(1)
    data= readCubeData(0,relY,1)
    print (0,",",relY,",",1,":",readCubeData(0,relY,1))
    sleep(.5)
    data= readCubeData(-1,relY,0)
    print (-1,",",relY,",",0,":",readCubeData(-1,relY,0))
    sleep(.5)
    data= readCubeData(0,y,-1)
    print (0,",",relY,",",-1,":",readCubeData(0,relY,-1))
    sleep(.5)
    data= readCubeData(1,y,0)
    print (1,",",relY,",",0,":",readCubeData(1,relY,0))
    sleep(.5)
end
start()

会产生一个输出

这只是悲剧性的错误，x，y，z值未指向正确的值，并且表也不打算在相同的x，y，z位置重复。我真的无法为我的生命解决这个问题