Gordon Linoff
2019-11-19 23:24:16
你不需要结构。你需要一个数组：
declare date_array array<date>;
set date_array = [date('2017-08-12'), date('2017-08-13'), date('2017-08-14')] ;
当然，你不会in为此目的而使用。你可以使用：
where date(my_time) in (select d from unnest(date_array) d)
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