tim_yates
2013-03-22 22:53:18
你可以使用findAll然后将结果转换为Integers：
def extractInts( String input ) {
input.findAll( /\d+/ )*.toInteger()
}
assert extractInts( "100 pounds is 23" ) == [ 100, 23 ]
assert extractInts( "I think 173 lbs" ) == [ 173 ]
assert extractInts( "73 lbs." ) == [ 73 ]
assert extractInts( "No numbers here" ) == []
assert extractInts( "23.5 only ints" ) == [ 23, 5 ]
assert extractInts( "positive only -13" ) == [ 13 ]
如果你需要小数和负数，则可以使用更复杂的正则表达式：
def extractInts( String input ) {
input.findAll( /-?\d+\.\d*|-?\d*\.\d+|-?\d+/ )*.toDouble()
}
assert extractInts( "100 pounds is 23" ) == [ 100, 23 ]
assert extractInts( "I think 173 lbs" ) == [ 173 ]
assert extractInts( "73 lbs." ) == [ 73 ]
assert extractInts( "No numbers here" ) == []
assert extractInts( "23.5 handles float" ) == [ 23.5 ]
assert extractInts( "and negatives -13" ) == [ -13 ]
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我最终根据上述建议实施了该解决方案，我只想获取第一个数字（如果有多个，我会使响应无效）。谢谢@tim_yates！
def extractNumericData(String response) { if(response) { def numberList = response.findAll( /[0-9]+.[0-9]*|[0-9]*.[0-9]+|[0-9]+/ ) if(numberList.size() == 1) { return numberList.get(0) as BigDecimal } else { return -1 } } }由于某种原因，我得到了：
java.lang.UnsupportedOperationException: spread not yet supported in input.findAll(\d+)*.toInteger()。----在詹金斯说它已经解决了。