Mateo977
2020-11-29 04:12:42
嵌套每个都不是执行此类任务的红宝石方法。你可以写这个
def remove_vowels(s)
nw_s = s.chars
vowels = "aeiou".chars
result = nw_s.map {|k| k unless vowels.include?(k) }.compact
end
remove_vowels("apple")
一行代码而不是七行
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要不就
"apple".scan(/[aeiou]/).join它返回“ ae”，Peter想从字符串中删除元音
好吧
"apple".scan(/[^aeiou]/).join，然后。"apple".delete("aeiou")