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java-我无法通过此代码找到最小的数字。

(java - I can't find smallest number by this code. How I find smallest number by modifying this code?)

发布于 2020-11-26 11:11:57

没有其他错误。我只是无法打印最小的输入。

public static void main(String args[]){
    Scanner input=new Scanner(System.in);
    System.out.print("Marks of a student(-1 to terminate the inputting marks): ");
    int x=input.nextInt();
    int total=0,large=0,y=0,small=0,z;
    z=x;
    while(x!=-1){
        System.out.print("Marks of a student(-1 to terminate the inputting marks): ");
        x=input.nextInt();
        total+=x;
        y++;
        if(x>=large){
            large=x;
        }
        if(x<small){
            small=x;
        }
    }
    int sum=total+z+1;
    double avg=(double)total/y;
    System.out.println("No of students: "+y);
    System.out.println("Total marks   : "+sum);
    System.out.println("Maximum       : "+large);
    System.out.println("Minimum       : "+small);
    System.out.println("Average       : "+avg);
}
Questioner
Pethum Jeewantha
Viewed
22
17.3k 2020-11-27 14:04:28

small用初始化0,因此任何大于该值的输入都将被忽略。

一种方法是使用初始化它Integer.MAX_VALUE,因此任何输入的数字都将小于或等于它。同样,large可以使用初始化Integer.MIN_VALUE