我有一种情况，我需要根据他们的职业来过滤用户，这是用户模式的定义方式：

const userSchema = new mongoose.Schema(
  {
    userData: {
      professions: [
        {
          type: mongoose.Schema.Types.ObjectId,
          ref: 'Profession'
        }
      ]
    }
  }
)

这是针对Professions模式的：

const ProfessionSchema = new mongoose.Schema(
  {
    name: {
      type: String,
      required: true,
      trim: true,
    }
  }
)

如何获得具有ID5f8ea4396586f1168ab3a298例如为ID的专业的用户列表？

我试过了

User.find({
    "userData.professions": { $elemMatch: $in: ["5f8ea4396586f1168ab3a298"] }
})

但是似乎这与我要尝试的相反。当我根据5f8ea4396586f1168ab3a298职业ID过滤结果时，需要得到这样的结果

[
    {
        "name": "John Doe",
        "userData": {
            "professions": ["5f8ea4396586f1168ab3a298", "5f8ea4226586f1168ab3a296"]
        }
    },
    {
        "name": "John Smith",
        "userData": {
            "professions": ["5f8ea4396586f1168ab3a298",]
        }
    },
    {
        "name": "Elon Musk",
        "userData": {
            "professions": ["5f8ea4466586f1168ab3a29a", "5f8ea4396586f1168ab3a298", "5f8ea4146586f1168ab3a295"]
        }
    }
]