我是Python的新手,最近学习了有关类的知识。我一直在尝试他们,并提出了一个学生/课程评分系统。这是到目前为止的代码:
class course:
TOTAL_COURSES = 0
def __init__(self, name, room, max_students):
self.name = name
self.room = room
self.max_students = max_students
self.student_list = []
course.TOTAL_COURSES += 1
def addStudent(self, student):
# Checks if the class is below max capacity
if len(self.student_list) < self.max_students:
self.student_list.append(student)
# Adds the course to the student's course list
student.course_list.append(self)
return True
return False
因此,这将创建一个课程班,我可以添加学生并设置他们的房间和其他内容。我还有另一堂课,旨在存储有关学生的信息:
class student:
TOTAL_STUDENTS = 0
def __init__(self, name, age, gender):
self.name = name
self.age = age
self.gender = gender
# Courses in course_list are stored as objects
self.course_list = []
student.TOTAL_STUDENTS += 1
很简单;我只是停留在如何创建实际的评分系统上。如果我要这样做:
s1 = student("Tom", 17, "Male")
c1 = course("English", "E123", 25)
然后可以使用“嵌套属性”吗?所以我将那个学生的课程成绩分配给一个像这样的值:
s1.c1.grade = "A+"
但是,这不起作用,并抛出(预期的)AttributeError。所以我必须使用以前创建的course_list吗?
s1.course_list[0].grade = "A+"
即使那样,我也不确定如何为该课程对象分配成绩。
这是通过为学生分配“课程位置”而不是课程本身来解决上述一些问题的解决方案。你可能会想到,可用的课程槽位数量受到限制,具体取决于课程的最大大小。该代码可以进一步开发,但是我认为这对入门非常有用:
class Student:
def __init__(self, name, age, gender):
self.name = name
self.age = age
self.gender = gender
self.courses = {}
def addCourse(self, course):
if course.status=='Enrolled':
self.courses[course.name] = course
else:
self.courses[course.name] = course.status
class Course:
def __init__(self, name, room, max_students):
self.name = name
self.room = room
self.max_students = max_students
self.student_list = []
self.course_slots_filled = 0
self.course_slots_available = max_students
def __str__(self):
return 'Course_object_{}'.format(self.name)
def check_slots_available(self):
if self.course_slots_filled < self.max_students:
return True
else:
return False
class CourseSlot:
def __init__(self, name, student_name, status):
self.name = name
self.student_name = student_name
self.status = status
self.grade = 'No grade assigned'
def __repr__(self):
return 'CourseSlot_object_{}'.format(self.name)
def set_grade(self, grade):
self.grade = grade
def assign_course_slot(self, student_name):
if self.check_slots_available():
self.course_slots_filled+=1
self.course_slots_available-=1
status = 'Enrolled'
self.student_list.append(student_name)
else:
print('Sorry, {} class is full! {} not enrolled.'.format(self.name, student_name))
status = 'Not enrolled'
return self.CourseSlot(self.name, student_name, status)
用法示例
实例化课程:
physics = Course('Physics','101',5)
chemistry = Course('Chemistry','102',1)
实例化学生1并分配课程时段:
s1 = Student("Tom", 17, "Male")
s1.addCourse(physics.assign_course_slot(s1.name))
s1.addCourse(chemistry.assign_course_slot(s1.name))
s1.courses['Physics'].set_grade('A+')
[v for v in s1.courses.values()]
# >>> [CourseSlot_object_Physics, CourseSlot_object_Chemistry]
实例化学生2并分配课程时段
s2 = Student("Susan", 18, "Female")
s2.addCourse(physics.assign_course_slot(s2.name))
s2.addCourse(chemistry.assign_course_slot(s2.name))
#>>> Sorry, Chemistry class is full! Susan not enrolled.
获取课程信息:
print('Physics course slots filled: ',physics.course_slots_filled)
print('Physics course slots available: ',physics.course_slots_available)
print('Chemistry course slots filled: ',chemistry.course_slots_filled)
print('Chemistry course slots available: ',chemistry.course_slots_available)
#>>> Physics course slots filled: 2
# Physics course slots available: 3
# Chemistry course slots filled: 1
# Chemistry course slots available: 0
print('Physics student list: ',physics.student_list)
print('Chemistry student list: ',chemistry.student_list)
# >>> Physics student list: ['Tom', 'Susan']
# Chemistry student list: ['Tom']
for s in [s1,s2]:
for c in s.courses.values():
try:
print('{} {} grade: {}'.format(s.name, c.name, c.grade))
except AttributeError:
pass
# >>> Tom Physics grade: A+
# Tom Chemistry grade: No grade assigned
# Susan Physics grade: No grade assigned
我猜作弊是,该课程student_list
仅获取学生的姓名,而不是Student对象的名称,如果你将其传递给唯一的ID,然后遍历Student对象的列表以匹配ID,则可能会起作用。无论如何都要考虑一下。