David W
2020-05-26 00:15:37
因为所有字符都可以用ASCII码表示（“ a”开头为97，所以所有ASCII码都为int），因此你可以简单地循环执行该操作。例如：
char albet[26];
for (int ch = 'a'; ch <= 'z'; ch++) {
//do ch-'a' because we start at index 0
albet[ch-'a'] = ch;
}
你就完成了！
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