我想在使用SQLAlchemy 1.1.5的Postgresql数据库中拥有一个uuid类型的主键ID,并使用pg8000适配器连接到该数据库。我使用了SQLAlchemy文档中与后端无关的GUID类型的配方。
当我想插入数据库时,出现以下错误
File ".../guid.py", line ???, in process_result_value
return uuid.UUID(value)
File "/usr/lib/python2.7/uuid.py", line 131, in __init__
hex = hex.replace('urn:', '').replace('uuid:', '')
AttributeError: 'UUID' object has no attribute 'replace'
我的模特看起来像这样
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy import Column, Integer, String
from guid import GUID
import uuid
base = declarative_base()
class Item(base):
__tablename__ = 'item'
id = Column(GUID(), default=uuid.uuid4, nullable=False, unique=True, primary_key=True)
name = Column(String)
description = Column(String)
def __repr__(self):
return "<Item(name='%s', description='%s')>" % (self.name, self.description)
我的资源或控制器如下所示
data = req.params
item = Item(name=data['name'], description=data['description'])
self.session.add(item)
self.session.commit()
的pg8000
PostgreSQL数据库适配器返回一个uuid.UUID()
对象(参见其类型映射文档,和SQLAlchemy的已通过该给TypeDecorator.process_result_value()
方法。
文档中给出的实现需要一个字符串,但是,这失败了:
>>> import uuid
>>> value = uuid.uuid4()
>>> uuid.UUID(value)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/Users/mjpieters/Development/Library/buildout.python/parts/opt/lib/python2.7/uuid.py", line 133, in __init__
hex = hex.replace('urn:', '').replace('uuid:', '')
AttributeError: 'UUID' object has no attribute 'replace'
快速的解决方法是强制将值改为字符串:
def process_result_value(self, value, dialect):
if value is None:
return value
else:
return uuid.UUID(str(value))
或者你可以先测试类型:
def process_result_value(self, value, dialect):
if value is None:
return value
else:
if not isinstance(value, uuid.UUID):
value = uuid.UUID(value)
return value
我已提交拉取请求#403来解决此问题(自合并以来)。