现在，当我们看到一些代码时，我的猜测似乎是正确的。如果你似乎误解了fork工作原理...

如果成功，它实际上会返回两次！一次在父进程中，一次在子进程中。在子进程中，你不应继续循环，而应先进行一些“工作”，然后再进行exit。父进程应继续循环以创建进程，然后执行其自身的处理，然后才能最终获得所有子进程。

简而言之：

pid_t pid_matrix[ROW][COL];

for (size_t row = 0; row < ROW; ++row)
{
    for (size_t col = 0; col < COL; ++col)
    {
        pid_matrix[row][col] = fork();

        if (pid_matrix[row][col] == -1)
        {
            // Error! Handle it some nice way
        }
        else if (pid_matrix[row][col] == 0)
        {
            // In the child process...
            // TODO: Do some work here!
            printf("In a new child process with pid %d\n", getpid());

            exit(EXIT_SUCCESS);  // Terminate the child process

            // Note that because the child-process have now exited,
            // the loop will not continue
        }
        else
        {
            // In the parent process
            printf("Created a new process with pid %d\n", pid_matrix[row][col]);

            // Note that we don't exit or do anything special here
            // This will let the loops continue as normal
        }
    }
}

_{[如何获得（释放资源）子进程作为练习留给读者]}