gcharita
2020-12-28 04:00:46
你可以使用以下代码从字典中提取标题和正文userInfo：
let aps = userInfo["aps"] as? [String: Any]
let alert = aps?["alert"] as? [String: String]
let title = alert?["title"]
let body = alert?["body"]
print(title ?? "nil")
print(body ?? "nil")
更新：如果你想用来Codable映射所有可能的字段，则要困难一些。
你可以创建一个这样的模型：
struct Payload: Decodable {
let aps: APS
let acme1: String?
let acme2: [String]?
}
struct APS: Decodable {
let alert: Alert
let badge: Int?
}
struct Alert: Decodable {
let title: String
let body: String?
let action: String?
}
然后，你必须使用将userInfo字典转换回Data，JSONSerialization最后使用解码数据JSONDecoder：
let decoder = JSONDecoder()
do {
let data = try JSONSerialization.data(withJSONObject: userInfo)
let payload = try decoder.decode(Payload.self, from: data)
print(payload.aps.alert.title)
print(payload.aps.alert.body ?? "nil")
} catch {
print(error)
}
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那正是我要寻找的