PaulB
2021-03-03 22:59:47
你的代码并不是你想要实现的真正最佳实践。仅在柱形开始时执行操作的最佳方法如下：
void OnTick()
{
if(TimeBar==Time[0])
{
//Carry out any operations on each tick here
return;
}
if(TimeBar==0)
{
// Operations carried out on First Run only here
TimeBar=Time[0];
return;
}
// Operations at the start of a new bar here
TimeBar=Time[0];
return;
}
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谢谢你，非常感谢。