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java-csv 数据通过测试方法

(java - Csv data pass Test method)

发布于 2021-11-19 07:28:12

我尝试将CSV数据传递给我的测试方法。

这是我的代码:CSV文件有3列:

  1. 测试编号
  2. 电子邮件
  3. 名字

用户数据.java

public class UserData {
    private String TestNumber;
    private String email;
    private String FirstName;
    
    //Getters and Setters

}

数据提供者类:

 @DataProvider(name = "customer" )
   public static Object[][] getFilterValues() throws InvalidFormatException, IOException, InterruptedException, CsvException {
        CSVReader reader= new CSVReaderBuilder(new FileReader("/home/dell/scripts/TEST/Automation - CSV/src/TestData/User.csv")).
                withSkipLines(1).
                build();

        List<UserData> csv_objectList=reader.readAll().stream().map(data-> {
            UserData csvObject= new UserData();
            csvObject.setTestNumber(data[0]);
            csvObject.setEmail(data[1]);
            csvObject.setFirstName(data[2]);
            return csvObject;
        }).collect(Collectors.toList());


        UserData[] cellData = csv_objectList.toArray(new UserData[csv_objectList.size()]);
        Object[][] data = new Object[cellData.length][3];

        for(int i = 0; i <cellData.length; i++) {

            data[i][0] = cellData[i].getTestNumber();
            data[i][1] = cellData[i].getEmail();
            data[i][2] = cellData[i].getFirstName();


        }
       
        return data;
    }

测试方法:

public class UserCreate extends Base {

    @Test( dataProvider = "customer", dataProviderClass = GetUserData.class)
    public  void   UserCreate (UserData data) throws FileNotFoundException {

        System.out.println(data.getTestNumber());
    }
}

我尝试了这种方式来传递数据。但我得到这个错误:

[public void api.wapp.registation.UserCreate.UserCreate(utilities.UserData) throws java.io.FileNotFoundException] has no parameters defined but was found to be using a data provider (either explicitly specified or inherited from class level annotation).
Data provider mismatch
Method: UserCreate([Parameter{index=0, type=utilities.UserData, declaredAnnotations=[]}])
Arguments: [(utilities.UserData) utilities.UserData@301ec38b,null,null]
Questioner
lahiru dilruwan
Viewed
0
Gautham M 2021-11-19 16:57:37

你的测试方法期望作为参数。但是你的数据提供者正在提供.在数据提供器方法中,将 的值传递到对象数组中,而不是传递对象本身。UserDataString, String, StringUserDataUserData

在数据提供器方法中,你要做的是,将每个对象放在一个中,该对象将组合成一个.UserDataObject[]Object[][]

return csv_objectList.stream()
                     .map(user -> new Object[]{ user }) // this array represents a single test case
                     .toArray(Object[][]::new);