c# 通过XDocument类型获取元素

Krishna Muppalla 2020-01-31 22:20

输入XML。更正了名称空间。

<?xml version="1.0" encoding="utf-8" ?>
<Body xmlns:i="http://tempuri.org/body">
  <Address>
    <Segment i:type="AddressSegment">
      <Id>9999</Id>
    </Segment>
  </Address>
  <Segmentation>
    <Segment xmlns:d4p1="http://tempuri.org/foo" i:type="d4p1:FooSegment">
      <d4p1:Id>63</d4p1:Id>
    </Segment>
    <Segment xmlns:d4p1="http://tempuri.org/bar" i:type="d4p1:BarSegment">
      <d4p1:Id>159</d4p1:Id>
    </Segment>
    <Segment i:type="BasicSegment">
      <Id>10</Id>
    </Segment>
  </Segmentation>
</Body>

使用xmltocsharp为FooSegment和BooSegment创建了模型类

[XmlRoot(ElementName = "Segment")]
public class FooSegment
{
    [XmlElement(ElementName = "Id", Namespace = "http://tempuri.org/foo")]
    public List<string> Id { get; set; }
    [XmlAttribute(AttributeName = "d4p1", Namespace = "http://www.w3.org/2000/xmlns/")]
    public string D4p1 { get; set; }
    [XmlAttribute(AttributeName = "type", Namespace = "http://tempuri.org/body")]
    public string Type { get; set; }
}

[XmlRoot(ElementName = "Segment")]
public class BarSegment
{
    [XmlElement(ElementName = "Id", Namespace = "http://tempuri.org/bar")]
    public List<string> Id { get; set; }
    [XmlAttribute(AttributeName = "d4p1", Namespace = "http://www.w3.org/2000/xmlns/")]
    public string D4p1 { get; set; }
    [XmlAttribute(AttributeName = "type", Namespace = "http://tempuri.org/body")]
    public string Type { get; set; }
}

使用此模型使用XmlSerializer反序列化

XDocument xml = XDocument.Load("1.xml");
XNamespace ns = "http://tempuri.org/body";

string[] values = new string[] { "d4p1:FooSegment", "d4p1:BarSegment" };
var result = xml.Root.DescendantsAndSelf("Segment")
    .Where(r => values.Contains((string)r.Attribute(ns + "type").Value));

foreach (var nodeValue in result)
{
    if(nodeValue.Attribute(ns + "type").Value.ToString() == "d4p1:FooSegment")
    {
        var fooObject = (FooSegment)new XmlSerializer(typeof(FooSegment)).Deserialize(new StringReader(nodeValue.ToString()));
        Console.WriteLine($"{fooObject.Id[0]}");
    }
    else
    {
        var barObject = (BarSegment)new XmlSerializer(typeof(BarSegment)).Deserialize(new StringReader(nodeValue.ToString()));
        Console.WriteLine($"{barObject.Id[0]}");
    }                
}

输出量

63
159

grmihel 2020-01-31 21:47:57

如果我想将FooSegment和BarSegment的XML结构分开，那么我可以将XML反序列化为Foo和Bar对象的POCO吗？有什么建议？

Krishna Muppalla 2020-01-31 22:12:11

@grmihel，是的，您可以在循环中反序列化。请检查示例代码

c# - 通过XDocument类型获取元素

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