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javascript - 丹戈

发布于 2020-03-31 23:27:18

我一直在尝试将数据从AJAX调用转换view.py为HTML并重新转换为HTML:

jQuery / JavaScript

    function getCookie(name) {
        var cookieValue = null;
        if (document.cookie && document.cookie !== '') {
            var cookies = document.cookie.split(';');
            for (var i = 0; i < cookies.length; i++) {
                var cookie = cookies[i].trim();
                // Does this cookie string begin with the name we want?
                if (cookie.substring(0, name.length + 1) === (name + '=')) {
                    cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
                    break;
                }
            }
        }
        return cookieValue;
    }

    function csrfSafeMethod(method) {
        // these HTTP methods do not require CSRF protection
        return (/^(GET|HEAD|OPTIONS|TRACE)$/.test(method));
    }

    $(document).ready(function(){ 

        var csrftoken = getCookie('csrftoken');

        $.ajaxSetup({
            beforeSend: function(xhr, settings) {
                if (!csrfSafeMethod(settings.type) && !this.crossDomain) {
                    xhr.setRequestHeader("X-CSRFToken", csrftoken);
                }
            }
        });

        // AJAX CALL TO VIEW
        $('a.play').click(function(e){
            e.preventDefault();
            var song_id = $(this).attr('id');
            alert(song_id);
            $.ajax({
                url: $(this).data('href'),
                type: 'POST',
                content: 'application/json; charset=utf-8',
                data: {
                    'song_id': song_id
                },
                dataType: 'json',
                success: function(html) {
                    alert(html);
                    $('.player').replaceWith(html);
                },
            });
        });
    });

views.py

    from django.shortcuts import render
    from django.http import Http404, JsonResponse
    from django.core import serializers
    from django.template.loader import render_to_string

    from .models import Song

    def change_song(request):
        if request.method == "POST":
            request.session['featured_song'] = request.POST.get('song_id', '')
            featured_song_id = request.session['featured_song']
            obj = Song.objects.get(pk=featured_song_id)
            song_list = Song.objects.all().order_by('-date') # list of objects
        context = {
            "featured_song": obj,
            "song_list": song_list,
        }
        return render_to_string("music/player.html", context)

因此,在收到AJAX调用的POST之后,我尝试将其返回以提醒其内容(调试)。第一个警报song_id按原样应返回ID,第二个警报甚至不会运行。当尝试调试时(我不记得确切的情况),当它运行时,第二个alert()仅返回整个html页面,而不仅仅是该部分。

注意: music/player.html在视图上基本上是.player容器。它没有包含,扩展或扩展其他模板的块。

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提问者
user3291759
被浏览
24
user3291759 2020-01-31 19:37

因此,我最终解决了这个问题。一直是模板/网址问题...

我想访问子APP的URL路径href="/change/",但没有填写APP的完整URL href="/music/change/"我的想法是,由于模板位于“音乐” APP的模板文件夹中,因此该URL仅需要该URL的/change/一部分。

话虽如此,我仍然在这里发布代码以供将来参考,因为我还修复了一些JSON处理,以防万一有人需要使用类似的东西。

views.py

def change_song(request):
    featured_song_id = request.session['featured_song']
    song_list = Song.objects.all().order_by('-date') # list of objects
    if request.method == "POST":
        request.session['featured_song'] = request.POST['song_id']
        featured_song_id = request.session['featured_song']
    obj = Song.objects.get(pk=featured_song_id)
    serialized_obj = serializers.serialize('json', [obj])
    serialized_song_list = serializers.serialize('json', song_list)
    string_render = render_to_string('music/player.html')
    context = {
        'html': string_render,
        'obj': serialized_obj,
        'song_list': serialized_song_list,
    }
    return JsonResponse(context, safe=False)

AJAX / jQuery / Javascript

    $('a.play').click(function(e){
        e.preventDefault();
        var song_id = $(this).attr('id');
        var this_url = $(this).attr('href');
        $.ajax({
            type: 'POST',
            url: this_url,
            data: {
                'song_id': song_id,
            },
            dataType: 'json',
            success: function(data) {
                obj = JSON.parse(data.obj);
                title = obj[0]['fields']['title'];
                $('.replace').replaceWith(data.html);
                $('.player-title').html(title);
            }
        });
    });

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