Nina Scholz
2020-01-31 19:56
只需检查at的值b是否与给定索引和后代相同。
const
a = ['a', 'b', 'c', 'd'];
b = [1, 1, 2, 1],
result = a.reduce((r, v, i) => {
if (b[i - 1] === b[i]) r[r.length - 1] += v;
else r.push(v);
return r;
}, []);
console.log(result);热门帖子
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