regex - 如何使用python从txt文件中打印格式化的文本？

您可以尝试不使用正则表达式，而仅使用字符串操作：

data = '''# Query 1: 204.60k QPS, 230.79x concurrency, ID XXXXXXXXXX at byte 19XXX9318
# This item is included in the report because it matches --limit.
# Scores: V/M = 0.00
# Time range: 2020-01-29 18:18:59.073995 to 18:18:59.074005
# Attribute    pct   total     min     max     avg     95%  stddev  median
# ============ === ======= ======= ======= ======= ======= ======= =======
# Count          7       2
# Exec time     10     2ms     1ms     1ms     1ms     1ms    12us     1ms
# Rows affecte   0       0       0       0       0       0       0       0
# Query size     7      74      37      37      37      37       0      37
# Warning coun   0       0       0       0       0       0       0       0
# String:
# Hosts        10.1.1.5 (1/50%), 10.8.0.2 (1/50%)
# Query_time distribution
#   1us
#  10us
# 100us
#   1ms  ################################################################
#  10ms
# 100ms
#    1s
#  10s+
SHOW SESSION STATUS LIKE 'XXXXX'\G
\n break line 
repeat
'''

data = data.split('\n')

all_results = []

result = []

for row in data:
    if row.startswith('# Query ') and not row.startswith('# Query size'):
        row = row.split(':')[0].split('# ')[1]
        result.append(row)

    elif row.startswith('# Hosts'):
        row = row.replace('# Hosts', '').replace(' ', '').split(',')
        result.append(row[0].split('(')[0])
        result.append(row[1].split('(')[0])

    elif row.startswith('# Time range:'):
        row = row.replace('# Time range:', '').split('.')[0].strip()
        result.append(row)

    elif row.startswith('SHOW') and row.endswith('\G'):
        result.append(row)
        result = ', '.join(result)
        all_results.append(result)
        result = []

print(all_results)

    # output: "Query 1, 2020-01-29 18:18:59, 10.1.1.5, 10.8.0.2, SHOW SESSION STATUS LIKE 'XXXXX'\\G"