algorithm javascript svg

javascript - 如何检查在svg折线或po中单击的线的起点和终点

发布于 2020-04-05 20:45:48

我正在为我的游戏制作 map编辑器。我有一个svg,其中将包含许多<polyline>每当用户单击的任何行时<polyline>我把两件事当作信息。单击鼠标的坐标以及该折线的所有点的顺序。

我想检查单击线之间的那两个点是什么。

为此,我使用了距离公式。如果AB是一条线,我们要检查该点是否C在该线上。我们将检查的距离AB是否等于BC + AC

下面是我的代码。

const poly = document.getElementById("poly");

poly.onclick = function(e){
  const mousePos = [e.clientX,e.clientY];
  //console.log(mousePos)
  const points = poly.getAttribute('points').split(' ').map(x => x.split(',').map(Number));
  const res= points.find((p, i) => {
    let prevPoint = points[i-1];
    if(i === 0){
      prevPoint = points[points.length - 1];
    }
    return arePointsCollinear(prevPoint, p, mousePos)
  });
  if(res){
    console.log(res);
  }
}

const getDistance = (pointA, pointB) => {
   const dx = Math.pow(pointA[0] - pointB[0], 2);
   const dy = Math.pow(pointA[1] - pointB[1], 2);
   return Math.sqrt(dx + dy);
};

const arePointsCollinear = (
   pointA,
   pointB,
   pointC
) => {
   const totalDistance = getDistance(pointA, pointB);
   const deltaAC = getDistance(pointA, pointC);
   const deltaBC = getDistance(pointB, pointC);
   return totalDistance === deltaAC + deltaBC;
};
svg polyline{
  fill:none;
  stroke:black;
  stroke-width: 10
}
svg{
height:500px;
width:500px;
}
body{
padding: 0;
margin: 0;
}
<svg xmlns="http://www.w3.org/2000/svg">
  <polyline id="poly" points="100,100 150,200 250,150 100,100"/>
</svg>

上面代码中的问题是它没有考虑线的宽度。意味着我们恰好在行的中心单击以获取答案。我希望每当我单击线时都应该告诉该线的两点。

查看更多

提问者
Maheer Ali
被浏览
127
Alex L 2020-02-02 06:48

我有工作

https://codepen.io/Alexander9111/pen/rNaERKa

在此处输入图片说明

HTML:

<svg id="svg" height="500" width="500" xmlns="http://www.w3.org/2000/svg"> 
    <polyline id="poly" points="100,100 150,200 250,150 100,100"/>
</svg>

JS:

const svg = document.getElementById("svg");
const poly = document.getElementById("poly");
const poly_width = getComputedStyle(poly)['stroke-width'];
console.log(parseInt(poly_width));
const half_width = parseInt(poly_width) / 2;

poly.onclick = function(e){
  const mousePos = [e.clientX,e.clientY];
  console.log(mousePos)
  const points = poly.getAttribute('points').split(' ').map(x => x.split(',').map(Number));
  const res= points.find((p, i) => {
    let prevPoint = points[i-1];
    if(i === 0){
      prevPoint = points[points.length - 1];
    }
    return arePointsCollinear(prevPoint, p, mousePos)
  });
  if(res){
    console.log(res);
    const NS = 'http://www.w3.org/2000/svg';
    const circle = document.createElementNS(NS,'circle');
    circle.setAttribute('r', '5');
    circle.setAttribute('cx', res[0]);
    circle.setAttribute('cy', res[1]);
    svg.appendChild(circle);
    console.log('circle');
  }
}

const getDistance = (pointA, pointB) => {
   const dx = Math.pow(pointA[0] - pointB[0], 2);
   const dy = Math.pow(pointA[1] - pointB[1], 2);
   return Math.sqrt(dx + dy);
};

const arePointsCollinear = (
   pointA,
   pointB,
   pointC
) => {
   const totalDistance = getDistance(pointA, pointB);
   const deltaAC = getDistance(pointA, pointC);
   const deltaBC = getDistance(pointB, pointC);
   return deltaAC + deltaBC <= Math.sqrt(totalDistance**2 + half_width**2);
};

最重要的是return deltaAC + deltaBC <= Math.sqrt(totalDistance**2 + half_width**2);-我画了一张图来说明这是从哪里来的:

在此处输入图片说明

基本上,您需要考虑仍在笔划宽度内的最长路径。我相信这是(lengthAB ^ 2加half_stroke-width ^ 2)的平方根

更新

如果要添加线,则需要更改points.find()为,points.findIndex()则可以使用索引和prevIndex在点之间画一条线:

在此处输入图片说明

JS:

const svg = document.getElementById("svg");
const poly = document.getElementById("poly");
const poly_width = getComputedStyle(poly)['stroke-width'];
console.log(parseInt(poly_width));
const half_width = parseInt(poly_width) / 2;

poly.onclick = function(e){
  const mousePos = [e.clientX,e.clientY];
  console.log(mousePos)
  const points = poly.getAttribute('points').split(' ').map(x => x.split(',').map(Number));
  const res= points.findIndex((p, i) => {
    let prevPoint = points[i-1];
    if(i === 0){
      prevPoint = points[points.length - 1];
    }
    return arePointsCollinear(prevPoint, p, mousePos)
  });
  if(res != -1){
    console.log(res);
    const NS = 'http://www.w3.org/2000/svg';
    const line = document.createElementNS(NS,'line')
    // const circle = document.createElementNS(NS,'circle');
    // circle.setAttribute('r', '5');
    // circle.setAttribute('cx', points[res][0]);
    // circle.setAttribute('cy', points[res][1]);
    // svg.appendChild(circle);
    // console.log('circle');

    line.setAttribute('x1', points[res][0]);
    line.setAttribute('y1', points[res][1]);
    let prevIndex = (res === 0) ? (points.length - 1) : res - 1;
    line.setAttribute('x2', points[prevIndex][0]);
    line.setAttribute('y2', points[prevIndex][1]);
    svg.appendChild(line);
    console.log('line');
  }
}

const getDistance = (pointA, pointB) => {
   const dx = Math.pow(pointA[0] - pointB[0], 2);
   const dy = Math.pow(pointA[1] - pointB[1], 2);
   return Math.sqrt(dx + dy);
};

const arePointsCollinear = (
   pointA,
   pointB,
   pointC
) => {
   const totalDistance = getDistance(pointA, pointB);
   const deltaAC = getDistance(pointA, pointC);
   const deltaBC = getDistance(pointB, pointC);
   return deltaAC + deltaBC <= Math.sqrt(totalDistance**2 + (2*half_width)**2);
};