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2017-07-21 23:13
以下正则表达式提取括号之间的所有内容：
PS> $prog = [regex]::match($s,'\(([^\)]+)\)').Groups[1].Value
PS> $prog
SUB RAD MSD 50R III
Explanation (created with RegexBuddy)
Match the character '(' literally «\(»
Match the regular expression below and capture its match into backreference number 1 «([^\)]+)»
Match any character that is NOT a ) character «[^\)]+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the character ')' literally «\)»
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感谢您的回答。您能解释一下吗，或者我如何学习正则表达式？任何推荐的好网站。