温馨提示:本文翻译自stackoverflow.com,查看原文请点击:java - WARNING: No mapping found for HTTP request with URI[] in DispatcherServlet with name []
java jsp maven spring xml

java - 警告:在名称为[]的DispatcherServlet中找不到带有URI []的HTTP请求的映射

发布于 2020-04-14 10:27:12

我真的是Spring框架的新手,正在为为什么收到此警告而苦苦挣扎。我已经看过StackOverflow和Coderanch的问题,但似乎找不到我的错误。我什至尝试看过两次youtube Spring MVC教程,并且做的和Youtuber一样,但是仍然出现此错误。如果你们能帮助我,我将非常感谢。我将代码放在下面。

pom.xml

  xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
  <modelVersion>4.0.0</modelVersion>
  <groupId>com.telusko</groupId>
  <artifactId>DemoMVC2</artifactId>
  <packaging>war</packaging>
  <version>0.0.1-SNAPSHOT</version>
  <name>DemoMVC2 Maven Webapp</name>
  <url>http://maven.apache.org</url>
  <dependencies>
     <dependency>
            <groupId>junit</groupId>
            <artifactId>junit</artifactId>
            <version>3.8.1</version>
            <scope>test</scope>
        </dependency>
        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-context</artifactId>
            <version>4.1.8.RELEASE</version>
        </dependency>

        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-webmvc</artifactId>
            <version>4.1.8.RELEASE</version>
        </dependency>
        <dependency>
            <groupId>mysql</groupId>
            <artifactId>mysql-connector-java</artifactId>
            <version>5.1.36</version>
        </dependency>
        <dependency>
            <groupId>javax.servlet</groupId>
            <artifactId>jstl</artifactId>
            <version>1.2</version>
        </dependency>
  </dependencies>
  <build>
    <finalName>DemoMVC2</finalName>
  </build>
</project>

web.xml

<!DOCTYPE web-app PUBLIC
 "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
 "http://java.sun.com/dtd/web-app_2_3.dtd" >

<web-app>
  <display-name>Archetype Created Web Application</display-name>

  <servlet>
        <servlet-name>telusko</servlet-name>
        <servlet-class>
            org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>telusko</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
</web-app>

telusko-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:ctx="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
    http://www.springframework.org/schema/mvc
    http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-2.5.xsd ">


    <mvc:annotation-driven/>
    <ctx:component-scan base-package="com.telusko"></ctx:component-scan>
</beans>

index.jsp

<html>
<body>
<form action="add">
    <input type="text" name="t1"></input><br>
    <input type="text" name="t2"></input><br>
    <input type="submit"></input>
</form>
</body>
</html>

addController.java

package com.telusko;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;

@Controller
public class addController {
    @RequestMapping("/add")
    public void add() {
        return "display.jsp";
    }
}

display.jsp

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert title here</title>
</head>
<body>

    I'm here

</body>
</html>

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提问者
noseless
被浏览
166
161 2020-02-04 18:16

这是您创建的servlet。您已经在该类telusko创建了一个servlet DispatcherServlet然后用映射它/应用程序启动时,找不到映射到的函数/因此,您将不得不重新调整您的web.xml文件