Why if condition "(skaner.next() != int)" highlights as wrong?

Here skaner.next() will return a String object whereas int is a primitive data type and therefore both are not comparable. To check if token returned by skaner.next() is an int or not, you can use Integer.parseInt(skaner.next()) which converts String to int and throws a NumberFormatException if input is not a valid integer.

package folder;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
    Scanner skaner = new Scanner(System.in);

while (skaner.hasNext()){
    String x = skaner.next();
    try {
        int y = Integer.parseInt(x);
        System.out.println("That is an integer " + y);
    }
    catch(NumberFormatException e) {
        System.out.println("That is a string " + x);
        }
    }
    skaner.close();
    }
}

Check this link for reference.