You could do:
if ([1, 2].includes(x)) {
// ....
}
Or:
if ([1, 2].indexOf(x) > -1) {
// ....
}
Or:
switch (x) {
case 1:
case 2:
// ....
break;
default:
}
I don't think they're "lighter" than your solution though.
To check if x variable is equal to 1 or 2, i would do normally something like:
if (x === 1 || x === 2){
// ....
}
but this can get in some cases very cumbersome.
Edit :I'm working right now on this and writing the fonction name every time i think can be done in a cleaner manner:
if (
this.getNotificationStatus() === 'denied' ||
this.getNotificationStatus() === 'blocked'
)
Is there any other lighter way to write this?
THANKS
You could do:
if ([1, 2].includes(x)) {
// ....
}
Or:
if ([1, 2].indexOf(x) > -1) {
// ....
}
Or:
switch (x) {
case 1:
case 2:
// ....
break;
default:
}
I don't think they're "lighter" than your solution though.
Note:
includesdoesn't work prior ES2016.indexOfdoesn't supported in some old browsers (IE9 for example).Yes, and
includesdoesn't work in IE at all.