我想使用以下功能在运行于iOS 8的Cordova / hybrid应用程序上将JPEG的base64字符串转换为blob b64toBlob
。
b64toBlob = function(b64, onsuccess, onerror) {
var img = new Image();
img.onerror = onerror;
img.onload = function onload() {
var canvas = document.createElement('canvas');
canvas.width = img.width;
canvas.height = img.height;
var ctx = canvas.getContext('2d');
ctx.drawImage(img, 0, 0, canvas.width, canvas.height);
canvas.toBlob(onsuccess);
};
img.src = b64;
}
但是它给出了一个错误
Uncaught Error: TypeError: undefined is not a function (evaluating 'canvas.toBlob(onsuccess)')
当我们做
var imageData = "data:image/jpeg;base64," + imageData
b64toBlob(imageData,
function(imageBlob) {
uploadBlob(imageBlob)
}, function(error) {
console.log(error)
});
如何解决此错误?
试试看 请注意,dataURI
假定包含base64前缀。(例如:"data:image/jpeg;base64,"
)
function b64toBlob(dataURI) {
var byteString = atob(dataURI.split(',')[1]);
var ab = new ArrayBuffer(byteString.length);
var ia = new Uint8Array(ab);
for (var i = 0; i < byteString.length; i++) {
ia[i] = byteString.charCodeAt(i);
}
return new Blob([ab], { type: 'image/jpeg' });
}
用法:
...
var blob = b64toBlob(imageData);
var formData = new FormData();
formData.append("source", blob);
...
我尝试了您的功能,但出现了错误
Uncaught Error: InvalidCharacterError: DOM Exception 5: An invalid or illegal character was specified, such as in an XML name
。有任何想法吗?我将dataURI字符串复制到gist.githubusercontent.com/anonymous/5440ebd3ae72708a651b/raw/…
dataURI字符串应包含base64标头,例如“ data:image / jpeg; base64”,请让我知道它的用法。@Nyxynyx