Travis Gockel
2020-02-18 02:32
问题是operator<<文本编码方法，即使您已指定std::ofstream::binary。您可以put用来编写单个二进制字符或write输出多个字符。请注意，您负责将数据转换为其char表示形式。
std::bitset<8> bits = foo();
std::ofstream outfile("compressed", std::ofstream::out | std::ofstream::binary);
// In reality, your conversion code is probably more complicated than this
char repr = bits.to_ulong();
// Use scoped sentries to output with put/write
{
std::ofstream::sentry sentry(outfile);
if (sentry)
{
outfile.put(repr); // <- Option 1
outfile.write(&repr, sizeof repr); // <- Option 2
}
}
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Mamba is a new state space model architecture showing promising performance on information-dense data such as language modeling, where previous subquadratic models fall short of Transformers. It is based on the line of progress on structured state space models, with an efficient hardware-aware design and implementation in the spirit of FlashAttention.
(翻译：Mamba 是一种新的状态空间模型架构，在信息密集型数据（例如语言建模）上显示出良好的性能，而之前的二次模型在 Transformers 方面存在不足。它基于结构化状态空间模型的进展，并本着FlashAttention的精神进行高效的硬件感知设计和实现。)
谢谢你的回答。我还有一个问题，我会接受你的回答。在这一行中，
char repr = bits.to_ulong();您已经写了评论your conversion code is probably more complicated than this。这是什么意思铸造
unsigned long从返回to_ulong到一个char只会工作时，此位集使用8位或更少位。如果您使用更多的东西，事情将会变得更加复杂。好，知道了。谢谢！