温馨提示:本文翻译自stackoverflow.com,查看原文请点击:metatrader4 - How can I write mql4 code (EA) that marks the listed candle patterns with rectangles
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metatrader4 - 如何编写用矩形标记列出的蜡烛图案的mql4代码(EA)

发布于 2020-03-27 11:53:12

我是编写mql4代码的新手,如果在以下烛台模式出现时能得到一些绘制矩形的帮助,将不胜感激:

图。1:

图片取自https://imgur.com/a/fRoPzsm

Run code snippet

<blockquote class="imgur-embed-pub" lang="en" data-id="a/fRoPzsm"><a href="//imgur.com/a/fRoPzsm">Demand Zone 1</a></blockquote><script async src="//s.imgur.com/min/embed.js" charset="utf-8"></script>

图2:

图片取自https://imgur.com/a/4E8KE1R

Run code snippet

<blockquote class="imgur-embed-pub" lang="en" data-id="a/4E8KE1R" data-context="false"><a href="//imgur.com/a/4E8KE1R">Demand Zone 2</a></blockquote><script async src="//s.imgur.com/min/embed.js" charset="utf-8"></script>

图3:

图片取自https://imgur.com/a/h6D6o6R

Run code snippet

<blockquote class="imgur-embed-pub" lang="en" data-id="a/h6D6o6R"><a href="//imgur.com/a/h6D6o6R">Hidden Demand Zone</a></blockquote><script async src="//s.imgur.com/min/embed.js" charset="utf-8"></script>

和相应的供应区域,
并以指定的点数止损和止盈开立挂单。

请原谅我不直接包含图像。我没有足够的投票赞成这样做。

以下是链接图像中烛台图案的说明:

需求区

The general candlestick pattern (Demand Zone) occurs when at least two or more consecutive bullish candles (with the last bullish candle high being the high of the time period) are followed by one or more bearish candles whose high and low are lower than the last bullish candle. Then finally followed by a bullish candle that forms the new high. The rectangle area which is the Demand Zone is taken from the Open to the Low of the last last bearish candle.

Hidden Demand Zone

When a series of consecutive bullish candles has a candle with its low, lower than the previous candle and its High coinciding with its Close, then the Hidden Demand Zone is taken from the low to the open of the bullish candle.

The full explanation is available here for both demand and supply zones.

I am aware that bullish and bearish candles can be determined by


    if ( ( Open[1] - Close[1] ) > 0)
    {
      // candle is bearish
    }
    else
    {
      // candle is bullish
    }

I would really appreciate some help.

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提问者
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被浏览
120
Daniel Kniaz 2019-07-11 18:23

Seems these patterns are not fully described, so it is not possible to code them correctly. Ok, let us try with pattern#1. The conditions used for pattern(what seems reasonable from the picture):
1. check at start of the new bar(bar#0).
2. bar 1(which is bar#3 in MQL4 if we compute 0 as the current) must be bullish.
3. bar 2(bar#2) is bearish. (or N bars in case of pattern#2, N can be 2 or more) 4. bar 3(bar#1 in MT4) is bullish.
5. its high=close.
6. its high>high of bar#3.

enum EnmDir
 {
  LONG = 1,
  SHORT=-1,
  NONE = 0,
 };
int getCandleDirection(const int shift)
{
   const double open=iOpen(_Symbol,0,shift), close=iClose(_Symbol,0,shift);
   if(close-open>_Point/2.)
      return LONG;      //bullish
   if(open-close>_Point/2.)
      return SHORT;     //bearish
   return NONE;     //doji
}
bool isPattern1Detected(const EnmDir dir)
{
   if(dir==0)return(false);
   if(getCandleDirection(3)!=dir)
      return false; //rule#2
   if(getCandleDirection(2)+dir!=0)
      return false; //rule#3
   if(getCandleDirection(1)!=dir)
      return false; //rule#4
   if(dir>0)
   {
      if(iHigh(_Symbol,0,1)-iClose(_Symbol,0,1)>_Point/2.)
         return false;  //rule#5 for long
      if(iHigh(_Symbol,0,1)-iHigh(_Symbol,0,3)>_Point/2.)
         return true;   //rule#6 for long
      return false;     //if rule#6 is not hold
   }
   else
   {
      if(iClose(_Symbol,0,1)-iLow(_Symbol,0,1)>_Point/2.)
         return false;  //rule#5 for short
      if(iLow(_Symbol,0,3)-iLow(_Symbol,0,1)>_Point/2.)
         return true;   //rule#6 for short
      return false;     //if rule#6 is not hold
   }
}
bool isPattern2Detected(const EnmDir dir,const int numCandlesAgainst=1)
{
   if(dir==NONE)return(false);
   if(getCandleDirection(1)!=dir)
      return false; //rule#4
   for(int i=1;i<=numCandlesAgainst;i++)
   {
      if(getCandleDirection(1+i)!=dir)
         return(false); //rule#3 - checking that all numCandlesAgainst must be bearish
   }
   if(getCandleDirection(2+numCandlesAgainst)!=dir)
       return false; //rule#2
   if(dir>0)
   {
     if(iHigh(_Symbol,0,1)-iClose(_Symbol,0,1)>_Point/2.)
        return false;  //rule#5 for long
     if(iHigh(_Symbol,0,1)-iHigh(_Symbol,0,2+numCandlesAgainst)>_Point/2.)
        return true;   //rule#6 for long
     return false;     //if rule#6 is not hold
   }
   else
   {
     if(iClose(_Symbol,0,1)-iLow(_Symbol,0,1)>_Point/2.)
        return false;  //rule#5 for short
     if(iLow(_Symbol,0,2+numCandlesAgainst)-iLow(_Symbol,0,1)>_Point/2.)
        return true;   //rule#6 for short
     return false;     //if rule#6 is not hold
   }
}

您还需要什么?要检测矩形的HL?这很简单,规则很明确。让我们假设它们是:对于LONG,向上=条形#2的打开,向下=该条形的低。然后,

void detectRangeOfZone(double &top,double &bottom,const EnmDir dir)
{
    if(dir>0)
    {
        top=iOpen(_Symbol,0,2);
        bottom=iLow(_Symbol,0,2);
    }
    else if(dir<0)
    {
        top=iClose(_Symbol,0,2);
        bottom=iHigh(_Symbol,0,2);
    }
}

您需要画一个矩形吗?好的,但是您将如何决定何时停止绘制?让我们假设右边的N条就足够了,现在让我们忽略周末(如果要记住市场休市时的周末会稍微复杂一些)。

bool drawRectangle(const int dir,const double top,const double bottom)
{
    const datetime starts=iTime(_Symbol,0,2), ends=starts+PeriodSeconds()*N_bars;//time of start and end of the rectangle
    const string name=prefix+"_"+(dir>0?"DEMAND":"SUPPLY")+"_"+TimeToString(starts);//name would be unique sinse we use time of start of the range. DO NOT FORGET about prefix - it should be declared globally, you would be able to delete all the objects with 'ObjectsDeleteAll()' function that accepts prefix in one of its implementations.

    if(!ObjectCreate(0,name,OBJ_RECTANGLE,0,0,0,0,0))
    {
        printf("%i %s: failed to create %s. error=%d",__LINE__,__FILE__,name,_LastError);
        return false;
    }
    ObjectSetInteger(0,name,OBJPROP_TIME1,starts);
    ObjectSetInteger(0,name,OBJPROP_TIME2,ends);
    ObjectSetDouble(0,name,OBJPROP_PRICE1,top);
    ObjectSetDouble(0,name,OBJPROP_PRICE2,bottom);
    //add color, width, filling color, access modifiers etc, example is here https://docs.mql4.com/ru/constants/objectconstants/enum_object/obj_rectangle
    return true;
}

这是主要的块,不要忘了添加一个新的条形检查,否则该工具将在每个刻度上检查对象,这很浪费时间。字符串前缀=“”; //为所有对象添加一些唯一的前缀const int N_bars = 15; //本例中为15条

void OnDeinit(const int reason){ObjectsDeleteAll(0,prefix);}
void OnTick()
{
    if(!isNewBar())
        return;     //not necessary but waste of time to check every second

    const bool pattern1Up=isPattern1Detected(1), pattern1Dn=isPattern1Detected(-1);
    if(pattern1Up)
    {
        double top,bottom;
        detectRangeOfZone(top,bottom,1);
        drawRectangle(1,top,bottom);
        PlacePendingOrder(1,top,bottom);
    }
    if(pattern1Dn)
    {
        double top,bottom;
        detectRangeOfZone(top,bottom,-1);
        drawRectangle(-1,top,bottom);
        PlacePendingOrder(-1,top,bottom);
    }
}

int PlacePendingOrder(const EnmDir dir,const double oop,const double suggestedSl)
{
   const double lot=0.10;                  //FOR EXAMPLE, PUT YOUR DATA HERE
   const string comment="example for SOF";
   const int magicNumber=123456789;

   int cmd=dir>0 ? OP_BUY : OP_SELL;
   double price=(dir>0 ? Ask : Bid), spread=(Ask-Bid);
   if(dir*(oop-price)>spread)
      cmd+=(OP_BUYSTOP-OP_BUY);
   else if(dir*(price-oop)>spread)
      cmd+=(OP_BUYLIMIT-OP_BUY);

   int attempt=0, ATTEMPTS=5, SLEEP=25, SLIPPAGE=10, result=-1, error=-1;
   while(attempt<ATTEMPTS)
     {
      attempt++;
      RefreshRates();
      if(cmd<=OP_SELL)
        {
         price=dir>0 ? Ask : Bid;
         result=OrderSend(_Symbol,cmd,lot,price,SLIPPAGE,0,0,comment,magicNumber);
        }
      else
        {
         result=OrderSend(_Symbol,cmd,lot,oop,SLIPPAGE,0,0,comment,magicNumber);
        }
      if(result>0)
         break;
      error=_LastError;
      Sleep(SLEEP);
    }
  if(result>0)
    {
     if(OrderSelect(result,SELECT_BY_TICKET))
       {
        price=OrderOpenPrice();
        if(!OrderModify(result,price,suggestedSl,0,OrderExpiration()))
           printf("%i %s: failed to modify %d. error=%d",__LINE__,__FILE__,result,_LastError);
           //tp is zero, sl is suggested SL, put yours when needed
       }
     return result;
    }
    printf("%i %s: failed to place %s at %.5f. error=%d",__LINE__,__FILE__,EnumToString((ENUM_ORDER_TYPE)cmd),(cmd>OP_SELL ? oop : price),error);
    return -1;
}