You could ignore the time portion of the date string
$date1 = new DateTime(date('Y-m-d', strtotime("2013-08-07 13:00:00")));
$date2 = new DateTime(date('Y-m-d', strtotime("2013-08-08 12:00:00")));
echo $date1->diff($date2)->days; // 1
What is the simplest way to get the difference in days between two PHP DateTimes, considering midnight as a day change (just like the DATEDIFF(DAY) SQL function does)?
For example, between today at 13:00 and tomorrow at 12:00, I should get 1 (day), even though the interval is less than 24 hours.
$date1 = new DateTime("2013-08-07 13:00:00");
$date2 = new DateTime("2013-08-08 12:00:00");
echo $date1->diff($date2)->days; // 0
You could ignore the time portion of the date string
$date1 = new DateTime(date('Y-m-d', strtotime("2013-08-07 13:00:00")));
$date2 = new DateTime(date('Y-m-d', strtotime("2013-08-08 12:00:00")));
echo $date1->diff($date2)->days; // 1
how can I get
hoursdifference?Will this diff method return a number or a string? I'm in the middle of a similar situation and I need to use the difference for some calculations.
Aditya I found it here stackoverflow.com/questions/15688775/…